SOLUTION: Garrett's coin bank contains 500 nickels, dimes, and quarters. He has the same number of nickels as dimes and a total value of $72.50. How many quarters does he have?
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Garrett's coin bank contains 500 nickels, dimes, and quarters. He has the same number of nickels as dimes and a total value of $72.50. How many quarters does he have?
Log On
Question 1181288: Garrett's coin bank contains 500 nickels, dimes, and quarters. He has the same number of nickels as dimes and a total value of $72.50. How many quarters does he have? Answer by ikleyn(52900) (Show Source):
x nickels
x dimes
and the rest (500-2x) coins are quarters.
Keeping it in mind, you write the total money equation
5x + 10x + 25(500-2x) = 7250 cents.
Simplify and find x
5x + 10x - 50x + 25*500 = 7250
25*500 - 7250 = 50x - 5x - 10x
52500 = 35x
x = = 150.
ANSWER. The number of quarters is 500 - 2*150 = 200.
Solved (using one equation for one single unknown, ONLY).