SOLUTION: What is the difference in area between the inscribed circle and the circumscribed circle in a 12-gon of edge length 2cm?

Algebra ->  Polygons -> SOLUTION: What is the difference in area between the inscribed circle and the circumscribed circle in a 12-gon of edge length 2cm?      Log On


   



Question 1181238: What is the difference in area between the inscribed
circle and the circumscribed circle in a 12-gon of
edge length 2cm?

Found 3 solutions by MathLover1, Edwin McCravy, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

we need a diagonals across 6 sides (d%5B6%5D), 5 sides (d%5B5%5D), 4 sides (d%5B4%5D), 3 sides(d%5B3%5D) , and 2 sides (d%5B2%5D)
d%5B6%5D=%28sqrt%286%29%2Bsqrt%282%29%29%2Aa ........given a=2cm
d%5B6%5D=%283.863703305156273%29%2A2cm
d%5B6%5D=7.727cm
d%5B5%5D+=+%28+2+%2B+sqrt%283%29+%29+%2A+2=7.464cm
d%5B4%5D+=+%28%28+3%2Asqrt%282%29+%2B+sqrt%286%29+%29+%2F+2%29+%2A+2=6.692cm
d%5B3%5D+=+%28+sqrt%283%29+%2B+1+%29+%2A+2=5.464cm
d%5B2+%5D=+%28%28+sqrt%286%29%2Bsqrt%282%29+%29+%2F+2%29%2A+2=+d%5B6%5D+%2F+2=3.864cm
then radius of circumcircle is:
r%5Bc%5D+=+d%5B6%5D+%2F+2+=+d%5B2%5D=3.864cm
r%5Bc%5D+=+3.864cm
A%5Bcc%5D=%283.864cm%29%5E2%2Api ...........where cc stands for circumcircle
A%5Bcc%5D=14.93%2Api%2Acm%5E2
radius of incircle is:
r%5Bi%5D=+d%5B5%5D+%2F+2=7.464%2F2=3.732cm
r%5Bi%5D=3.732cm
A%5Bic%5D=%283.732cm%29%5E2%2Api...........where ic stands for incircle
A%5Bic%5D=13.93%2Api%2Acm%5E2
the difference in area between the inscribed circle and the circumscribed circle in a 12-gon is
A%5Bcc%5D-A%5Bic%5D=14.93%2Api%2Acm%5E2-13.93%2Api%2Acm%5E2=pi




Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
A regular 12-gon is made of 12 triangles (not drawn to scale), where the
angle at the left is 1/12th of 2π or π/6. 



Draw in the arcs of the two circles and a horizontal line dividing the (isosceles) triangle into two congruent right triangles.



The radius of the circumscribed (larger) circle is the hypotenuse h, of
the upper right triangle and the radius of the inscribed (smaller)
circle is the side adjacent, x, to the π/12 angle.

We find the hypotenuse h:

sin%28pi%2F12%29=1%2Fh
h=1%2Fsin%28pi%2F12%29
h=csc%28pi%2F12%29

We find the adjacent side x:

tan%28pi%2F12%29=1%2Fx
x=1%2Ftan%28pi%2F12%29
x=cot%28pi%2F12%29


The area of the larger circle is 
pi%2Ah%5E2

The area of the smaller circle is 
pi%2Ax%5E2

The difference in the areas is

pi%2Ah%5E2-pi%2Ax%5E2%29
pi%22%22%2A%22%22%28h%5E2-x%5E2%29
pi%22%22%2A%22%22%28csc%5E2%28pi%2F12%29-cot%5E2%28pi%2F12%29%5E%22%22%29

By a well-known identity the expression in parentheses is 1.

Therefore the required difference is

pi%281%29 or

pi.

Edwin


Answer by ikleyn(52858) About Me  (Show Source):
You can put this solution on YOUR website!
.

    I look into the solution by  @MathLover1,  and  I  ask myself :    . . . WHAT  it  WAS . . .  ?


                         . . . No answer . . .