SOLUTION: Solve. square root of 4x+4 -8=0 2+ square root of 3x-2 = 0

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Question 118121: Solve.
square root of 4x+4 -8=0

2+ square root of 3x-2 = 0

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
square root of 4x+4 -8=0
:
sqrt%284x%2B4%29 - 8 = 0
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Add 8 to both sides:
sqrt%284x%2B4%29 = 8
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Square both sides and you have:
4x + 4 = 64
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subtract 4 from both sides:
4x = 64 - 4
4x = 60
Divide both sides by 4
x = 60%2F4
x = 15
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You can substitute 15 for x in the original equation and check our solution
:
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2+ square root of 3x-2 = 0
:
2 + sqrt%283x-2%29 = 0
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Subtract 2 from both sides
sqrt%283x-2%29 = -2
You can see that his will not have a solution, but we can proceed with the method:
Square both sides:
3x - 2 = +4
3x = 4 + 2
3x = 6
x = 6%2F3
x = 2
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Substitute 2 for x in the original equation
2 + sqrt%283%282%29-2%29 = 0
2 + sqrt%284%29} = 0
2 + 2 does not = 0 so this is not a solution
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