SOLUTION: Find three consecutive integers such that the sum of the first two decreased by the third equals 68.

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Question 118114: Find three consecutive integers such that the sum of the first two decreased by the third equals 68.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive integers such that the sum of the first two decreased by the third equals 68.
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1st = x
2nd = x+1
3rd = x+2
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EQUATION:
x+x+1-(x+2)= 68
x-1 = 68
x = 69
x+1=70
x+2=71
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Cheers,
Stan H.