SOLUTION: I need to learn how to factor completly 3x^2 + 17x + 10

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Question 118105: I need to learn how to factor completly
3x^2 + 17x + 10

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 3x%5E2%2B17x%2B10 we can see that the first term is 3x%5E2 and the last term is 10 where the coefficients are 3 and 10 respectively.

Now multiply the first coefficient 3 and the last coefficient 10 to get 30. Now what two numbers multiply to 30 and add to the middle coefficient 17? Let's list all of the factors of 30:



Factors of 30:
1,2,3,5,6,10,15,30

-1,-2,-3,-5,-6,-10,-15,-30 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 30
1*30
2*15
3*10
5*6
(-1)*(-30)
(-2)*(-15)
(-3)*(-10)
(-5)*(-6)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 17? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 17

First NumberSecond NumberSum
1301+30=31
2152+15=17
3103+10=13
565+6=11
-1-30-1+(-30)=-31
-2-15-2+(-15)=-17
-3-10-3+(-10)=-13
-5-6-5+(-6)=-11



From this list we can see that 2 and 15 add up to 17 and multiply to 30


Now looking at the expression 3x%5E2%2B17x%2B10, replace 17x with 2x%2B15x (notice 2x%2B15x adds up to 17x. So it is equivalent to 17x)

3x%5E2%2Bhighlight%282x%2B15x%29%2B10


Now let's factor 3x%5E2%2B2x%2B15x%2B10 by grouping:


%283x%5E2%2B2x%29%2B%2815x%2B10%29 Group like terms


x%283x%2B2%29%2B5%283x%2B2%29 Factor out the GCF of x out of the first group. Factor out the GCF of 5 out of the second group


%28x%2B5%29%283x%2B2%29 Since we have a common term of 3x%2B2, we can combine like terms

So 3x%5E2%2B2x%2B15x%2B10 factors to %28x%2B5%29%283x%2B2%29


So this also means that 3x%5E2%2B17x%2B10 factors to %28x%2B5%29%283x%2B2%29 (since 3x%5E2%2B17x%2B10 is equivalent to 3x%5E2%2B2x%2B15x%2B10)

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Answer:

So 3x%5E2%2B17x%2B10 factors to %28x%2B5%29%283x%2B2%29