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Question 1180977: A shop sells calculators and phones.
2/3 of the calculators is equal to 6/11 of the phones in the shop.
There are a total of 260 phones and calculators in the shop.
Each calculator at the shop cost the shopkeeper $18.
If the shopkeeper sells all the calculators at a price of $23.45 each, how much will he earn?
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
A key to one way to solve a problem like this, in which the given information is that 2/3 of the calculators is equal to 6/11 of the phones, is to rewrite the two fractions with like NUMERATORS.
2/3 = 6/9
So 6/9 of the calculators is equal to 6/11 of the phones.
That means there are 9 calculators for every 11 phones.
So let the numbers of calculators be 9x and the number of phones be 11x. The total number of calculators and phones is 260:
9x+11x=260
20x=260
x=13
number of calculators: 9(13)=117
number of phones: 11(13)=143
The profit for selling each calculator is $23.45-$18 = $5.45.
The profit from selling 117 calculators is 117($5.45) = $637.65.
It must be assumed, from the way the problem is presented, that "how much will he earn" is asking for the profit he gets from selling the calculators -- not considering the phones.
ANSWER: $637.65
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