Question 1180947: A certain type of bacteria, given a favorable growth medium, doubles in population every 6.5 hours. Given that there were approximately 100 bacteria to start with, how many bacteria will there be after one and a half days?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website! -----------------------------------------------------------------------
..., doubles in population every 6.5 hours. Given that there were approximately 100 bacteria to start with, how many,...
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x in HOURS
and one and half a day is 36 hours;
.
.
Answer by ikleyn(52803)  (Show Source):
You can put this solution on YOUR website! .
A certain type of bacteria, given a favorable growth medium, doubles in population every 6.5 hours.
Given that there were approximately 100 bacteria to start with, how many bacteria will there be
after one and a half days?
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With the doubling peroiod of 6.5 hours and initial population of 100 bacteria,
the current population, as the function of time, is n(t) = 100*2^(t/6.5), where t is the time in hours.
To find the population in 1.5 days = 1.5*24 = 36 hours, the fotmula is
n(36 hours) = 100*2^(36/6.5).
Use your calculator.
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Solved.
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To see many other similar and different solved problems on bacteria growth, look into the lesson
- Bacteria growth problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Logarithms".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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