SOLUTION: 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls
per minute. For a 1 minute period,
a. Find the expected value.
b. Find
Algebra ->
Probability-and-statistics
-> SOLUTION: 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls
per minute. For a 1 minute period,
a. Find the expected value.
b. Find
Log On
Question 1180933: 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls
per minute. For a 1 minute period,
a. Find the expected value.
b. Find the probability of receiving no more than 2 calls. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The mean/expected value of the Poisson distribution is the parameter, here 5 calls per minute.
no more than two calls is p(0,1,2)
probability of 0 calls is e^-5*5^0/0!=0.0067
1 call is e^-5*5^1/1!=0.0337
2 calls is e^-5*5^2/2!=0.0842
that sum is 0.1246 rounding each step 0.1247 using no rounding until the end (preferred).
