SOLUTION: Find A so that Ax - 4y + 3 = 0 is: a. perpendicular to the line 2x + 2y -5 = 0 b. parallel to the line 2x + 2y -5 = 0

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Find A so that Ax - 4y + 3 = 0 is: a. perpendicular to the line 2x + 2y -5 = 0 b. parallel to the line 2x + 2y -5 = 0       Log On


   

Question 1180745: Find A so that Ax - 4y + 3 = 0 is:
a. perpendicular to the line 2x + 2y -5 = 0
b. parallel to the line 2x + 2y -5 = 0
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
Slope for Ax-4y%2B3=0 is A%2F4.
Slope for 2x%2B2y-5=0 is -1.

Second line and first line perpendicular:
A%2F4=-%28-1%29
A%2F4=1
highlight%28A=4%29

The "A" line parallel to line of 2x%2B2y-5=0:
highlight%28A=-4%29
Or slopes of both need to be the same value, that of negative One.