SOLUTION: 2^x-2 = 32 how do i write that in logarithmic form?

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Question 1180696: 2^x-2 = 32
how do i write that in logarithmic form?
Found 4 solutions by josgarithmetic, MathLover1, ikleyn, MathTherapy:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
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2^x-2 = 32
how do i write that in logarithmic form?
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You show 2x%5E2-2=32.
You very likely want or have something else.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2%5E%28x-2%29=+32
b%5Ey+=+x is equivalent to y+=+log%28b%2Cx%29+
in your case b=2, y=%28x-2%29, and x=32
x-2=+log%282%2C32%29+
x=+log%282%2C32%29+%2B2-> log form
solution:
x=+log%282%2C2%5E5%29+%2B2
x=+5log%282%2C2%29+%2B2
x=+5%2A1+%2B2
x=+7+

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
2%5E%28x-2%29 = 32   in logarithmic form is


     +-----------------------------+
     |   x-2 = log%282%2C%2832%29%29.          |
     +-----------------------------+


And by the way,  log%282%2C%2832%29%29 = 5,  since  32 = 2%5E5.

Solved.



Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

2^x-2 = 32
how do i write that in logarithmic form?
If it's matrix%281%2C3%2C+2%5E%28x+-+2%29%2C+%22=%22%2C+32%29, then in LOGARITHMIC form, it's 

Next time, use PARENTHESES.

According to a tutor on this forum, they're FREE, so why not use them!!