Question 118054: in the 1998 Grand Prix inaustralia, Mika Hakkinen completed the fastes lap in a time of 1 minute 31.649 seconds. His average speed was 208.303 kilmetres per hour for that lap. calculate the length of the lap, to the nearest metre.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! in the 1998 Grand Prix inaustralia, Mika Hakkinen completed the fastes lap in a time of 1 minute 31.649 seconds. His average speed was 208.303 kilmetres per hour for that lap. calculate the length of the lap, to the nearest metre.
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Time = 91.649 seconds = 91.649secs / [3600 sec/hr] = 0.0255 hrs.
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Rate = 208.303 kph
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Distance = tr = 0.0255 hrs*208.303 k/hr = 5.3030 km = 5303 meters
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Cheers,
Stan H.
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