Question 1180515: A scientist is worried about a new disease being spread by mosquitoes in an area. The scientist captures a random sample of 137 mosquitoes from the area and tests them to find out whether they carry the disease. In this sample, 22 of the mosquitoes were carrying the disease.
Using this information, the scientist uses 100 simulations of additional samples with the same proportion of disease-carrying mosquitoes from the sample to determine that the standard deviation for the proportion of mosquitoes carrying the disease is approximately 0.029.
What is the margin of error for the estimated proportion of mosquitoes in the area that carry the disease?
A.
0.029
B.
0.321
C.
0.161
D.
0.058
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The margin of error is the SEM * z, and z isn't given here. If it is a 95% CI, z would be 1.96, which would make the best answer 0.058.
A. Is std error of mean
B and C are too large
D. is the best answer.
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