SOLUTION: A cyclist and a jogger set out at 11 a.m. from the same point, headed in the same direction. The average speed of the cyclist is twice the average speed of the jogger. In 1 hour,

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Question 1180488: A cyclist and a jogger set out at 11 a.m. from the same point, headed in the same direction. The average speed of the
cyclist is twice the average speed of the jogger. In 1 hour, the cyclist is 7 km ahead of the jogger. Find the rate of the
cyclist.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
%282r-r%29%2A1=7
r=7

jogger speed, 7 km per hour
Cyclist speed, 14 km per hour