Question 1180447: From a bag containing 4 white and 6 black balls, two balls are drawn at random. If the
balls are drawn one after the other without replacement, find the probability that
3.1 both balls are white.
3.2 both balls are black.
3.3 the first ball is white and the second ball is black.
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website! 3.1 (4/10)*(3/9)
3.2 (6/10)*(5/9)
3.3 (4/10)*(6/9)
NOTE that in 3.3, the order matters. If we didn't care about order and just wanted P(you end up with one white and one black) = (6/10)*(4/9) + (4/10)*(6/9), which happens to be twice that found in 3.3, and is also equal to 1 - ((3.1) +(3.2)) which should make sense intuitively (you select two balls, they are either both black, both white, or one of each color).
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