SOLUTION: The area of the region under the curve given by the function f(x) = 2x2 + 6 on the interval [0, b] is 36 square units, where b > 0. The value of b is ? a. 1 b. 2 c. 3 d. 4

Algebra ->  Surface-area -> SOLUTION: The area of the region under the curve given by the function f(x) = 2x2 + 6 on the interval [0, b] is 36 square units, where b > 0. The value of b is ? a. 1 b. 2 c. 3 d. 4      Log On


   



Question 1180435: The area of the region under the curve given by the function f(x) = 2x2 + 6 on the interval [0, b] is 36 square units, where b > 0.
The value of b is ?
a. 1
b. 2
c. 3
d. 4

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
.
The area of the region under the curve given by the function f(x) = 2x2 + 6 on the interval [0, b] is 36 square units, where b > 0.
The value of b is ?
a. 1
b. 2
c. 3
d. 4
~~~~~~~~~~~~~

The area under the curve is the integral of the given function from 0 to value of "b".


This integral is equal to  %282%2F3%29b%5E3+%2B+6b.


So we need find "b" from equation


    %282%2F3%29b%5E3+%2B+6b = 36,

or

    2b%5E3+%2B+18b = 108.


The function on the left is monotonically increasing function of "b", 

so if we guess the value, it is the unique solution.


Easy guessing gives  b = 3 as the solution.    ANSWER

Solved.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The area as a function of b is given by
int%28%282x%5E2+%2B+6%29%2Cdx%2C0%2Cb%29=%282%2F3%29b%5E3%2B6b


You want to find b such that a%2Ab+=+36.
%282%2F3%29b%5E3+%2B6b+=+36. . . . multiply by 3%2F2+to clear fractions
b%5E3+%2B9b+-54+=+0 . . . .factor
%28b+-+3%29+%28b%5E2+%2B+3b+%2B+18%29+=+0

so, this equation to have one real solution at b=3

The value of b is 3.