SOLUTION: An electronics store sells 60 entertainment systems per month at $800 each. For every $20 increase in the selling price, the store sells one fewer system. What should the store set

Algebra ->  Finance -> SOLUTION: An electronics store sells 60 entertainment systems per month at $800 each. For every $20 increase in the selling price, the store sells one fewer system. What should the store set      Log On


   



Question 1180421: An electronics store sells 60 entertainment systems per month at $800 each. For every $20 increase in the selling price, the store sells one fewer system. What should the store set the price to in order to maximize the revenue? What is the maximum revenue? Determine an algebraic solution.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
PRICE           QUANT.         REV.
800               60
800+1*20          60-1
800+2*20          60-2

.
.
800-20x          60-x      (800-20x)(60-x)

Revenue is %28800-20x%29%2860-x%29;
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