SOLUTION: Eight years ago Charles was 1 year older than twice David’s age then. In eight years, Charles will be 7/6 as old as David will be then. What is David’s age now ?

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Question 1180400: Eight years ago Charles was 1 year older than twice David’s age then. In eight years, Charles will be 7/6 as old as David will be then. What is David’s age now ?
Found 3 solutions by josgarithmetic, ewatrrr, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website!
------exact translation of the description; c for Charles' age and d for David's age

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The problem description is nonsense.
NO SOLUTION.

Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!

Hi Let c and d represent their respective ages NOW: c- 8 = 2(d-8) + 1 c + 8 = (7/6)(d+8) c - 2d = -7 c - (7/6)d = 56/6 - 48/6 - c + 2d = 42/6 c - (7/6)d = 8/6 (5/6)d = 50/6 d = 10, David's age NOW c = 13 NOW 5 = 2(2) + 1 checks Wish You the Best in your Studies.

Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!
Eight years ago Charles was 1 year older than twice David’s age then. In eight years, Charles will be 7/6 as old as David will be then. What is David’s age now ?

There's nothing "FUNNY" about this problem.
The lady tutor is correct. INDEED,
So, IGNORE the person who claims that it's NONSENSE, and that no solutions exist!
What he did and what he says are NONSENSE!