Question 1180393: Solve cos2x = 1 - sinx for 0° < x < 360°. In terms of angles
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Using the trig identity cos(2x) = 1 - 2sin^2(x), we have:
1 - 2sin^2(x) = 1 - sin(x) -> sin(x)(2sin(x) - 1) = 0
This equation is satisfied if either sin(x) = 0 or 2sin(x) = 1
sin(x) = 0 -> x = 0, pi
sin(x) = 1/2 -> x = pi/6, 5pi/6
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