You can put this solution on YOUR website! given the vertices of A(7,9), B(-5,-7) and (12,-3) of triangle ABC find the equation of the side AB?
equation of line given two points
(y-y1)/(y1-y2) = (x-x1)/(x1-x2)
(y-9)/(9-(-7)) = (x-7)/(7-(-5))
(y-9)/16 = (x-7)/12
12(y-9) = 16(x-7)
12y-108= 16x -112
12y = 16x -4
/12
y = (4/3)x -(1/3)