SOLUTION: Greg had 1/3 as many calendar to sell as Kenzo. The two friends decided to share the work evenly. To do that, Kenzo gave 10 calendars to Greg. What was the total number of calendar

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Greg had 1/3 as many calendar to sell as Kenzo. The two friends decided to share the work evenly. To do that, Kenzo gave 10 calendars to Greg. What was the total number of calendar      Log On


   

Question 1180253: Greg had 1/3 as many calendar to sell as Kenzo. The two friends decided to share the work evenly. To do that, Kenzo gave 10 calendars to Greg. What was the total number of calendars?
Found 2 solutions by Boreal, ankor@dixie-net.com:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
G=(1/3)K
(1/3)K+10=K-10
(2/3)K=20
K=30, after multiplying both sides by the reciprocal 3/2
G=10
The answer is 40 calendars.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
g = no. of calendars that Greg had
k = no. that Kenzo had
:
Greg had 1/3 as many calendar to sell as Kenzo.
g = 1%2F3k
Get rid of fraction, multiply by 3
3g = k
The two friends decided to share the work evenly. To do that, Kenzo gave 10 calendars to Greg.
g + 10 = k - 10
g = k - 10 - 10
g = k - 20
replace k with 3g
g = 3g - 20
20 = 3g - g
20 = 2g
g = 20/2
g = 10 calendars
then
k = 3(10)
k = 30 calendars
:
What was the total number of calendars?
10 + 30 = 40