SOLUTION: A lake is stocked with 500 fish, and the fish population P increases according to the logistics curve P=10,000/1+19e^-t/5, t greater or equal than 0, where t in the time in months.
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-> SOLUTION: A lake is stocked with 500 fish, and the fish population P increases according to the logistics curve P=10,000/1+19e^-t/5, t greater or equal than 0, where t in the time in months.
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Question 1180182: A lake is stocked with 500 fish, and the fish population P increases according to the logistics curve P=10,000/1+19e^-t/5, t greater or equal than 0, where t in the time in months.
A)Find the population in fish after 5 months.
B)After how many months will the fish population reach 2000. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! P(5)=10000/(1+19e^(-1)=10000/7.989=1431, rounded to nearest integer.
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2000=10000/(1+19 e^(-t/5))
1+19e*(-t/5)=5, dividing both sides by 2000
19e^(-t/5)=4
e^(-t/5)=4/19
ln both sides
-t/5=-1.558
t=7.79 months.
