SOLUTION: The cost (c) of materials for a deck varies jointly with the width (w) and the length (l). If c = $470.40 when w = 12 and l = 16, find the cost when w = 10 and l = 25?

Algebra ->  Finance -> SOLUTION: The cost (c) of materials for a deck varies jointly with the width (w) and the length (l). If c = $470.40 when w = 12 and l = 16, find the cost when w = 10 and l = 25?      Log On


   



Question 1180075: The cost (c) of materials for a deck varies jointly with the width (w) and the length (l).
If c = $470.40 when w = 12 and l = 16, find the cost when w = 10 and l = 25?

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
The cost (c) of materials for a deck varies jointly with the width (w) and the length (l).
If c = $470.40 when w = 12 and l = 16, find the cost when w = 10 and l = 25?
c alpha wl
c= kwl
c = $470.40 when w = 12 and l = 16,
470 = k 12*16
470.40 = 192 k
470.40/90 =k
k=6.23
c= 6.23 *10*25 =1557.5