SOLUTION: Two promotional stands are to be placed in an ellipse-shaped room—one at each foci—and are 3 units from the center. If the room is 8 units wide, what is its length? a. √5

Algebra ->  Finance -> SOLUTION: Two promotional stands are to be placed in an ellipse-shaped room—one at each foci—and are 3 units from the center. If the room is 8 units wide, what is its length? a. √5       Log On


   



Question 1180069: Two promotional stands are to be placed in an ellipse-shaped room—one at each foci—and are 3 units from the center. If the room is 8 units wide, what is its length?
a. √5 units
b. √4 units
c. √8 units
d. √7 units
e. √3 units

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

We are given the value of a and c;
a is the width of the ellipse and c is the focus of the ellipse
for an ellipse the equation to be used to find b or the length of the ellipse is:
a%5E2+=+b%5E2+%2B+c%5E2
substitute the values in the equation to solve for the missing variable:
c=3
8 units is 2a, therefore, a+=+4
4%5E2+=+b%5E2+%2B+3%5E2
solve for b:
+b%5E2=+4%5E2+-+3%5E2
+b%5E2=16+-+9
b+=+sqrt%287+%29 units
Therefore, the value of b is +sqrt%287+%29units and your answer is
d. +sqrt%287+%29 units