SOLUTION: A soccer ball was hit and moved upward at a 50.0° angle with an initial velocity of 40.0 m/s.
a. Find the length of time of flight.
b. What is the horizontal distance reached
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a. Find the length of time of flight.
b. What is the horizontal distance reached
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Question 1180006: A soccer ball was hit and moved upward at a 50.0° angle with an initial velocity of 40.0 m/s.
a. Find the length of time of flight.
b. What is the horizontal distance reached by the soccer ball?
c. What is the maximum vertical distance reached by the soccer ball?
Thanks. Answer by ikleyn(52901) (Show Source):
You can put this solution on YOUR website! A soccer ball was hit and moved upward at a 50.0° angle with an initial velocity of 40.0 m/s.
a. Find the length of time of flight.
b. What is the horizontal distance reached by the soccer ball?
c. What is the maximum vertical distance reached by the soccer ball?
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I will solve the problem as physicists and the Physics students do it . . .
Having given the vector v as v = (40 m/s, 50°), calculate first its horizontal and verical components
= 40*cos(50°) = 40*0.643 = 25.725 m/s;
= 40*sin(50°) = 40*0.765 = 30.630 m/s.
(a) the length of time flight = = = 6.245 seconds.
Here g = 9.81 m/s^2 is the gravity acceleration.
(b) the horizontal distance = = 25.725*6.245 = 160.65 meters.
(c) the maximum vertical distance height = = = 47.82 meters.
