SOLUTION: A bulb is 70% efficient. It produces 49 kWh of light energy. How much energy is inputted? (include units and if necessary, round to 2 decimal places).

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Question 1179882: A bulb is 70% efficient. It produces 49 kWh of light energy. How much energy is inputted? (include units and if necessary, round to 2 decimal places).

Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let x be the inputted energy.


Then the problem says


    0.7x = 49 kWh.


It means


    x = 49%2F0.7 kWh = 70 kWh.    ANSWER

Solved, answered and explained. And completed.