Question 117967: Can you please explain this to me?
Divide:
2x^2 + 5x - 12
_______________ divided 2x^2 - 7x + 6
9x^2 - 16 _____________
3x^2 - x -4
thank you
Julie Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Divide:
2x^2 + 5x - 12
_______________ divided 2x^2 - 7x + 6
9x^2 - 16 _____________
3x^2 - x -4
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Factor where you can:
[(2x^2+8x-3x-12)/(3x-4)(3x+4)] / [(2x^2-3x-4x+6)/(3x^2-4x+3x-4)]
=[(2x(x+4)-3(x+4))/(3x-4)(3x+4)] / [(x(2x-3)-2(2x-3))/(x(3x-4)+(3x-4)]
= [(x+4)(2x-3)/(3x-4)(3x+4)] / [(2x-3)(x-2)/(3x-4)(x+1)]
Cancel where you can:
Cancel (2x-3),(3x-4) leaving you with:
= [(x+4)/(3x+4)]/[(x-2)/(x+1)]
Invert the denominator and multiply:
= [(x+4)(x+1)]/[(3x+4)(x-2)]
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Cheers,
Stan H.
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