SOLUTION: Prove triangle xyz = 1/7 triangle ABC, where triangle xyz is formed by three segments between the vertices and the one third of the opposite sides of the triangle ABC.

Algebra ->  Geometry-proofs -> SOLUTION: Prove triangle xyz = 1/7 triangle ABC, where triangle xyz is formed by three segments between the vertices and the one third of the opposite sides of the triangle ABC.      Log On


   

Question 1179629: Prove triangle xyz = 1/7 triangle ABC, where triangle xyz is formed by three segments between the vertices and the one third of the opposite sides of the triangle ABC.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


Poor grammar and no discernible relationship between triangles ABC and XYZ.

Re-post so we don't have to guess what the question is.

Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.

This theorem of  Geometry is called  "One-seventh area triangle".

It is  FAR  ABOVE  elementary school geometry curriculum.


About this theorem,  see these links

https://en.wikipedia.org/wiki/One-seventh_area_triangle

https://en.wikipedia.org/wiki/Routh%27s_theorem