Question 1179558: Area Number of covid cases
A 92
B 56
C 107
D 37
E 52
What is the lower quartile of th given data?
A.37
B.52
C.92
D.107
Find the upper quartile of the lower quartile.
A.37
B.52
C.92
D.107
Find the average of the lower quartile and the upper quartile of the data
A. 99.5
D. 81.5
C. 74
D. 72
Answer by CPhill(1987)   (Show Source):
You can put this solution on YOUR website! **1. Finding the Lower Quartile**
First, we need to order the data from least to greatest:
37, 52, 56, 92, 107
The lower quartile (Q1) is the median of the lower half of the data. Since we have an odd number of data points, we don't include the median of the whole set when finding the lower half.
Lower half: 37, 52
The median of 37 and 52 is **52**.
**Therefore, the answer is B. 52**
**2. Finding the Upper Quartile**
The upper quartile (Q3) is the median of the upper half of the data.
Upper half: 92, 107
The median of 92 and 107 is **99.5**. (We would normally take the average of the two numbers, but since there are only two numbers in the upper half, the upper quartile is just the average of those two numbers.)
**Therefore, the answer is none of the above. The upper quartile is 99.5.**
**3. Finding the Average of the Lower and Upper Quartiles**
We found the lower quartile (Q1) to be 52 and the upper quartile (Q3) to be 99.5.
Average = (Q1 + Q3) / 2 = (52 + 99.5) / 2 = 151.5 / 2 = **75.75**
**Therefore, the answer is none of the above. The average is 75.75.**
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