SOLUTION: A circle has a centre of (0,0) and a radius of 13. Draw a circle with a centre of (0,0) and a radius of 13.  You may use Geogebra for this assignment, or some other graphing

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Question 1179512: A circle has a centre of (0,0) and a radius of 13.
Draw a circle with a centre of (0,0) and a radius of 13.  You may use Geogebra for this assignment, or some other graphing software, or you may draw the graph by hand on graph paper.
The points A(0, _ ) , B( _ ,0) and C( _, _ ) are points on the circle. From your graph, determine a possible value to fill in each blank for each point. The point C must not contain any zeroes in its coordinates.
Construct the chords AB and AC.
Construct the perpendicular bisectors of the chords.
Construct the intersection of the perpendicular bisectors of the chords. Where do the bisectors intersect?

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
A circle has a centre of (0,0) and a radius of 13.
Draw a circle with a centre of (0,0) and a radius of 13. 
You may use Geogebra for this assignment, or some other graphing software, or you may draw the graph by hand on graph paper.
using formula
x%5E2%2By%5E2=13%5E2
x%5E2%2By%5E2=169



The points A(0, _ ) , B( _ ,0) and C( _, _ ) are points on the circle.
From your graph, determine a possible value to fill in each blank for each point. The point C must not contain any zeroes in its coordinates.
Construct the chords AB and AC.
A(0, 13 ) , B( 13 ,0) and C( 0, 0 )

Construct the perpendicular bisectors of the chords.
the perpendicular bisector of AC is a line y=13%2F2=6.5 and the perpendicular bisector of AB is a line y=x



Construct the intersection of the perpendicular bisectors of the chords. Where do the bisectors intersect?
the bisectors are y=13%2F2=6.5 and y=x
if
y=6.5
y=x
=>x=6.5
the bisectors intersect at (6.5,6.5)




Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The solution from @MathLover1 is not correct: C(0,0) is NOT a point on the circle.

Otherwise the ideas of her solution are sound.

Since (5,12,13) is a Pythagorean Triple, use C(5,12) or C(12,5) as the third point on the circle, and follow her example using that.