SOLUTION: a coin purse contains four 1-peso coins, five 5- peso coin and six 10-peso coin. another coin purse contains four 1-peso coin five 5-peso coin and three 10-peso coins. if a coin is

Algebra ->  Permutations -> SOLUTION: a coin purse contains four 1-peso coins, five 5- peso coin and six 10-peso coin. another coin purse contains four 1-peso coin five 5-peso coin and three 10-peso coins. if a coin is      Log On


   

Question 1179433: a coin purse contains four 1-peso coins, five 5- peso coin and six 10-peso coin. another coin purse contains four 1-peso coin five 5-peso coin and three 10-peso coins. if a coin is taken from one of the two coin purses at random, what is the probability that it is a 5-peso coin? with solutions please. thank you.
Answer by ikleyn(52775) About Me  (Show Source):
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a coin purse contains four 1-peso coins, five 5-peso coins and six 10-peso coins.
another coin purse contains four 1-peso coins, five 5-peso coins and three 10-peso coins.
if a coin is taken from one of the two coin purses at random,
what is the probability that it is a 5-peso coin? with solutions please. thank you.
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It is with the probability  1%2F2  the coin is from the 1st or from the 2nd purse.


If the coin is from the 1st purse, then it is the probability  5%2F%284%2B5%2B6%29 = 5%2F15 = 1%2F3  that the coin is  a  5-peso.


If the coin is from the 2nd purse, then it is the probability  5%2F%284%2B5%2B3%29 = 5%2F12  that the coin is  a  5-peso.



THEREFORE, the probability under the problem's question is


    P = %281%2F2%29%2A%281%2F3%29 + %281%2F2%29%2A%285%2F12%29 = 1%2F6+%2B+5%2F24 = 4%2F24+%2B+5%2F24 = 9%2F24 = 3%2F8.    ANSWER


Solved, answered, explained and completed.

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