SOLUTION: A rectangle is 3 inches longer than it is wide. Numerically, its area exceeds its perimeter by 14. Find the perimeter. in

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Question 1179263: A rectangle is 3 inches longer than it is wide. Numerically, its area exceeds its perimeter by 14. Find the perimeter.
in
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions d and d+3

d%28d%2B3%29-2%28d%2Bd%2B3%29=14


d%5E2%2B3d-4d-6=14
d%5E2-d=20
d%28d-1%29=20

Width is 5.
Length is 8.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

L=W%2B3........eq.1
area: A=LW
perimeter:P=2%28L%2BW%29
its area exceeds its perimeter by 14
LW=2%28L%2BW%29%2B14..........substitute L from eq.1
%28W%2B3%29W=2%28W%2B3%2BW%29%2B14
W%5E2%2B3W=2%282W%2B3%29%2B14
W%5E2%2B3W=4W%2B6%2B14
W%5E2%2B3W-4W-20=0
W%5E2-W-20=0
%28W+-+5%29+%28W+%2B+4%29+=+0
=>W=+5 or W=+-4-> disregard negative solution
go to
L=W%2B3........eq.1, substitute W
L=5%2B3
L=8
then perimeter is:
P=2%28L%2BW%29
P=2%288%2B5%29
highlight%28P=26%29 inches

check if area exceeds its perimeter by 14:
A=LW
A=8%2A5
A=40
40-26=14