SOLUTION: Given that p is a whole number, and 1/4 < 2/p < 1/3, what is the value of p?

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Question 1179033: Given that p is a whole number, and 1/4 < 2/p < 1/3, what is the value of p?
Found 3 solutions by MathLover1, ikleyn, greenestamps:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

1%2F4+%3C+2%2Fp+%3C+1%2F3........divide by 2

%281%2F4+%29%2F2%3C+%282%2Fp%29%2F2+%3C+%281%2F3%29%2F2
1%2F8%3C+1%2Fp+%3C+1%2F6............if so, then
6%3C+p+%3C+8+ and =>p=7

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Your starting inequality is

    1%2F4 < 2%2Fp < 1%2F3


It is so called "compound inequality", and it is equivalent to two separate inequalities


    1%2F4 < 2%2Fp    (1)

and

    2%2Fp < 1%2F3,   (2)


connected by the service word "and".


From inequality (1), multiplying both sides by positive number 4p, you get an EQUIVALENT inequality

    p < 4*2 = 8.    (3)



From inequality (2), multiplying both sides by positive number 3p, you get an EQUIVALENT inequality

    p > 3*2 = 6.    (4)



So, from (3) and (4) you have

    6 < p < 8.


There is only one integer number, satisfying this compound inequality :  p = 7.    ANSWER

Solved.



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The algebraic solutions from the other tutors are fine.

But this problem is easily solved using a technique that is occasionally useful in comparing fractions.

In most problems where fractions are being compared, it is easiest to get a common denominator. But in a few kinds of problems, like this one, a solution is obtained more easily by making the numerators the same.

So in this problem convert the 1/4 and 1/3 into equivalent fractions with numerator 2, as in the fraction 2/p. Then you have

2%2F8+%3C+2%2Fp+%3C+2%2F6

From there the solution is trivial....

ANSWER: p=7