SOLUTION: 20 grams of an unknown compound decays continuously according to the model A = 20e-0.02t
where A is the amount of the compound remaining after t years. How long before the amount
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-> SOLUTION: 20 grams of an unknown compound decays continuously according to the model A = 20e-0.02t
where A is the amount of the compound remaining after t years. How long before the amount
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Question 1178995: 20 grams of an unknown compound decays continuously according to the model A = 20e-0.02t
where A is the amount of the compound remaining after t years. How long before the amount
of compound reaches one-fourth of its original amount?
You can put this solution on YOUR website! 20 grams of an unknown compound decays continuously according to the model:
A = 20e-0.02t where A is the amount of the compound remaining after t years.
How long before the amount of compound reaches one-fourth of its original amount?
:
1/4 of 20 grams is 5 grams, therefore
:
:
using natural logs
-.02t*ln(e) = ln(2.5)
ln of e is 1, therefore
-.02t = -1.3863
t = -1.3863/-.2
t = 69.3 years
