SOLUTION: A ball is thrown straight up from the top of a building 128 ft tall with an initial velocity of 80 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time
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s(t) (in feet)
of the ball from the ground, at time
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Question 1178859: A ball is thrown straight up from the top of a building 128 ft tall with an initial velocity of 80 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 128 + 80t − 16t2.
Find the maximum height attained by the ball. ft Answer by ewatrrr(24785) (Show Source):
Hi
the maximum height attained by the ball (in ft)
s(t) = 128 + 80t − 16t^ 2:
vertex: t = -b/(2a)
t = 80/32
t = 2.5sec
Using FREE graph software https://www.padowan.dk/download/
s(2.5sec) = 228ft
Wish You the Best in your Studies.
