Question 1178551: `A.) Grand prize for a lottery is choosing 6 numbers correctly out of 47 (order does not matter). What is the probability of winning this lottery?
B.) If you choose 6 numbers out of 47 and 5 are chosen correctly you win second prize. What is this probability.
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! probability of first's being correct is (6/47), and this is multiplied by (5/46)(4/45)(3/44)(2/43)(1/42)
that value is 720/7,731,052,560
=9.13 X 10^(-8)
or 1 in 10,737,573
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There are 6 ways to do this, and one way is
first number doesn't matter (probability 1)*(5/46)(4/45)(3/44)*(2/43)*1/42)=120/164,490,480.
But there are 6 ways this can occur, so the answer is 720/164,490,480
=4.38 x 10^(-6)
or 1 in 228,459
Answer by ikleyn(52855)  (Show Source):
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