SOLUTION: a goat is tied to a corner of a 30 ft by 35 ft building. if the rope is 40 ft long and the goat can reach 1 ft farther than the rope length, what is the maximum area the goat can c
Algebra ->
Surface-area
-> SOLUTION: a goat is tied to a corner of a 30 ft by 35 ft building. if the rope is 40 ft long and the goat can reach 1 ft farther than the rope length, what is the maximum area the goat can c
Log On
Question 1178371: a goat is tied to a corner of a 30 ft by 35 ft building. if the rope is 40 ft long and the goat can reach 1 ft farther than the rope length, what is the maximum area the goat can cover? Found 2 solutions by MathLover1, ikleyn:Answer by MathLover1(20850) (Show Source):
Given:
width of building = ft
length of building = ft
length of rope = ft
total reach of goat = ft
To solve for the total area, get the sum of the three areas.
Area 1 is equal to the one quarter of the area of a ft radius circle.
Area 2 is equals to the one quarter of the area of a ft radius circle.
Area 3 is equals to the three quarters of the area of a ft radius circle.
total area:
The accessible area is the disjoint union of 5 (five, FIVE) 90° circular sectors
= = = = = .
Therefore, the total accessible area is
A = = = 4084.07 square feet (rounded). ANSWER