SOLUTION: ​Gaby's piggy bank contains dimes and quarters worth $8.45. If she has 59 coins in​ all, how many of each does she​ have?

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Question 1178335: ​Gaby's piggy bank contains dimes and quarters worth $8.45. If she has 59 coins in​ all, how many of each does she​ have?
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let quarters be q and dimes d
if she has 59 coins in​ all, then
q%2Bd=59....solve for q
q=59-d
if she has total of $8.45, then
0.25q%2B0.10d=8.45........substitute q
0.25%2859-d%29%2B0.10d=8.45
14.75-0.25d%2B0.10d=8.45
14.75-0.15d=8.45
14.75-8.45=0.15d
6.30=0.15d
d=6.30%2F0.15
d=630%2F15
d=42
go to
q=59-d...substitute d
q=59-42
q=17
Gaby​ have 17 quarters and 42 dimes


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

​Gaby's piggy bank contains dimes and quarters worth $8.45. If she has 59 coins in​ all, how many of each does she​ have?
Let number of quarters be Q

Then number of dimes = 59 - Q

We then get: .25Q + .1(59 - Q) = 8.45

.25Q + 5.9 - .1Q = 8.45

.25Q - .1Q = 8.45 - 5.9

.15Q = 2.55

Number of quarters or highlight_green%28matrix%281%2C5%2C+Q%2C+%22=%22%2C+2.55%2F.15%2C+%22=%22%2C+17%29%29

Now find the number of dimes by subtracting 17 from 59.

That's IT!!