SOLUTION: find all real solutions of cot^(2)3θ=3

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Question 1178313: find all real solutions of cot^(2)3θ=3
Found 3 solutions by MathLover1, ikleyn, Solver92311:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

cot%5E2%283theta%29=3
cot%283theta%29=+sqrt%283%29

3theta=cot%5E-1%28sqrt%283%29%29
3theta=pi%2F6
theta=%28pi%2F6%29%2F3
theta=pi%2F18->theta=10°
or
3theta=cot%5E-1%28-sqrt%283%29%29
3theta=5pi%2F6
theta=5pi%2F18 ->theta=+50°


Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
.

            The solution by @MathLover1 is wrong.

            If you solve such problem at exam this way,  unsatisfactory score is guaranteed to you.

            Therefore,  I came to bring a correct solution.


From  cot%5E2+%283theta%29 = 3 you have two cases.


    a)  cot%283theta%29 = sqrt%283%29,  and

    b)  cot%283theta%29 = - sqrt%283%29.



Let's consider these cases separately.


a)  cot%283theta%29 = sqrt%283%29.


    Then 3theta = 30°  or  3theta = 210°;


         but since the problem talks about  3theta,  you must consider 
         
         also the angles        30° + 360° = 390°  and  30° + 720° = 750°;

         as well as the angles  210°+ 360° = 570°  and  210°+ 720° = 930°.


    These 6 angles for  3theta,         30°, 390°, 750°, 210°, 570° and 930°,  
    give 6 different angles for theta:  10°, 130°, 250°,  70°, 190° and 310°.




b)  Similarly  for  cot%283theta%29 = - sqrt%283%29.


    Then 3theta = 150°   or  3theta = 330°;


         but since the problem talks about  3theta,  you must consider 
         
         also the angles        150° + 360° = 510°  and  150° + 720° = 870°;

         as well as the angles  330° + 360° = 690°  and  330° + 720° =1050°.


    These 6 angles for         3theta,  150°, 510°, 870°, 330°, 690° and 1050°,  
    give 6 different angles for theta:   50°, 170°, 290°, 110°, 230° and 350°.



Finally, these  6 + 6 = 12 angles gives you the full 


ANSWER.   10°,  130°,  250°,  70°,  190° and 310°,

          50°,  170°,  290°,  110°,  230° and 350°.

Solved (correctly).



Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


















or



So



or




John

My calculator said it, I believe it, that settles it

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