SOLUTION: An urn contains 10 red balls and 7 yellow balls. If Vince chooses 7 balls at random from the urn, what is the probability that he will select 3 red balls and 4 yellow balls? Round
Algebra ->
Probability-and-statistics
-> SOLUTION: An urn contains 10 red balls and 7 yellow balls. If Vince chooses 7 balls at random from the urn, what is the probability that he will select 3 red balls and 4 yellow balls? Round
Log On
Question 1178298: An urn contains 10 red balls and 7 yellow balls. If Vince chooses 7 balls at random from the urn, what is the probability that he will select 3 red balls and 4 yellow balls? Round your answer to decimal places. Answer by ewatrrr(24785) (Show Source):
Hi
An urn contains 17 balls: "10 red balls and 7 yellow balls"
"chooses 7 balls"
P("3R & 4Y") = (10C3)(7C4)/(17C7) = 120*35/19448 = .216
Wish You the Best in your Studies.