SOLUTION: 16) Albert and Jack are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and packages of dahlia bulbs. Albert sold 14 packages of tulip bulbs

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Question 1178288: 16) Albert and Jack are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and packages of dahlia bulbs. Albert sold 14 packages of tulip bulbs and 3 packages of dahlia bulbs for a total of $267. Jack sold 7 packages of tulip bulbs and 13 packages of dahlia bulbs for a total of 352. Find the cost of one package of tulip bulbs and one package of dahlia bulbs.
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

x cost of one package of tulip bulbs
y cost of one package of dahlia bulbs


14.00 x + 3.00 y = 267.00 ...........1


7.00 x + 13.00 y = 352.00 .............2
Eliminate y
multiply (1)by -13.00
Multiply (2) by 3.00
-182.00 x -39.00 y = -3471.00
21.00 x 39.00 y = 1056.00
Add the two equations
-161.00 x = -2415.00
/ -161.00
x = 15.00
plug value of x in (1)
14.00 x + 3.00 y = 267.00
210.00 + 3.00 y = 267.00
3.00 y = 57.00
y = 19.00
Ans x = 15.00
y = 19.00
$ 15.00 cost of one package of tulip bulbs
$ 19.00 cost of one package of dahlia bulbs


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

16) Albert and Jack are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and packages of dahlia bulbs. Albert sold 14 packages of tulip bulbs and 3 packages of dahlia bulbs for a total of $267. Jack sold 7 packages of tulip bulbs and 13 packages of dahlia bulbs for a total of 352. Find the cost of one package of tulip bulbs and one package of dahlia bulbs.
I think this person who responded just loves to torture others by having them do COMPLEX and UNNECESSARY work.

Using 2 variables, T of tulip and D for dahlia, we get the following system of equations:

14T + 3D = 267 ------- eq (i)

7T + 13D = 352 ------- eq (ii)

14T + 26D = 704 ------ Multiplying eq (ii) by 2 ------ eq (iii) 

      23D = 437 ------ Subtracting eq (i) from eq (iii)

Number of dahlia bulbs, or highlight_green%28matrix%281%2C5%2C+D%2C+%22=%22%2C+437%2F23%2C+%22=%22%2C+19%29%29

Now, substitute 19 for D in eq (i) to find the value of T, the number of tulip bulbs!