SOLUTION: Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number

Algebra ->  Equations -> SOLUTION: Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number      Log On


   



Question 1178235: Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number
Found 3 solutions by ikleyn, josgarithmetic, greenestamps:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82.
Find the number
~~~~~~~~~~~~~~


Do not write "her own son".

The mother can not have a son, who is not "her own son".



. . . Do not frighten people who read your post . . .



Use the punctuation signs properly.


Also, which number you suppose to find ?


The number of stars in the sky ?


/////////////


By writing inaccurately, you deprive yourself of the opportunity to get the solution and explanations from qualified tutors . . .

If you will write in this mode, the tutors who respect themselves, will not communicate with you.




Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
----------------------------------------------------------------------
Five years ago a mother was twice as old as her own son in 6 years time the sum of their age will be 82. Find the number
-------------------------------------------------------------------
Which number?


-------
Five years ago, a mother was twice as old as her son. In 6 years time, the sum of their age will be 82. Find the current age of each.
-------

system%28m-5=2%28b-5%29%2C%28m%2B6%29%2B%28b%2B6%29=82%29--------this is the description. Do what you need to.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Given that the mother was twice as old as her son 5 years ago, I would set up the problem using

x = son's age 5 years ago
2x = mother's age 5 years ago

6 years from now is 11 years after 5 years ago, so....

x+11 = son's age 6 years from now
2x+11 = mother's age 6 years from now

The sum of their ages 6 years from now is 82:

%28x%2B11%29%2B%282x%2B11%29+=+82
3x%2B22+=+82
3x+=+60
x+=+20

Their ages 5 years ago were 20 and 40.
Their ages now are 25 and 45.
Their ages 6 years from now will be 31 and 51.

It's not clear from your post which "number" you wanted....