SOLUTION: Determine three consecutive even numbers such that the sum of four times the smallest number, twice the middle number and half of the biggest number is 32.

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Question 1178151: Determine three consecutive even numbers such that the sum of four times the smallest number, twice the middle number and half of the biggest number is 32.
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Determine three consecutive even numbers such that the sum of four times the smallest number, twice the middle number and half of the biggest number is 32.
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Use n, n+2 & n+4
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4n + 2(n+2) + (n+4)/2 = 32
etc


Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Three consecutive even integers can be represented by x, x%2B2, x%2B4.
if the sum of four times the smallest number, twice the middle number and half of the biggest number is 32, we have
4x%2B2%28x%2B2%29%2B%281%2F2%29%28x%2B4%29=32
4x%2B2x%2B4%2Bx%2F2%2B2=32
6.5x%2B6=32
6.5x=32-6
6.5x=26
x=26%2F6.5
x=4->the smallest number
x%2B2=4%2B2=6
x%2B4=4%2B4=8
your numbers are: 4,6, and 8