SOLUTION: Suppose that the number of cars arriving in 1 hour at a busy intersection is a Poisson probability distribution with λ = 100. Find, using Chebyshev’s inequality, a lower bound f

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose that the number of cars arriving in 1 hour at a busy intersection is a Poisson probability distribution with λ = 100. Find, using Chebyshev’s inequality, a lower bound f      Log On


   



Question 1178059: Suppose that the number of cars arriving in 1 hour at a busy intersection is a Poisson probability distribution with λ = 100. Find, using Chebyshev’s inequality, a lower bound for the probability that the number of cars arriving at the intersection in 1 hour is between 70 and 130.
Thank you :)

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
For the Poisson distribution, mu+=+100, and sigma%5E2+=+100, and so sigma+=+10.
Chebyshev's theorem says that P%28abs%28X+-+mu%29%3C=+k%2Asigma%29+%3E=+1-1%2Fk%5E2.
==> P%28abs%28X+-+100%29+%3C=+10k%29+%3E=+1-1%2Fk%5E2, and k has to be determined.
abs%28X+-+100%29+%3C=+10k+ is the same as -10k+%3C=+X+-+100+%3C=+10k, or 70+=+100-10k+%3C=+X+%3C=+100%2B10k+=+130.
This implies that k = 3. We then get P%28abs%28X+-+100%29+%3C=+30%29+%3E=+1-1%2F3%5E2+=+8%2F9.
Therefore a lower bound for probability of cars arriving at the intersection in 1 hour is between 70 and 130 is highlight%288%2F9%29.