Question 1178031: P(6,3) Q(4,7) and R(3,1) are the midpoints of the sides of the triangle ABC. Find the gradient of PQ. Find the equation of the line AB.Find the equation of the perpendicular bisector of the line AC.
Answer by mananth(16946)   (Show Source):
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The slope of a line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=(y2−y1)/(x2−x1.)
We have that x1=6, y1=3, x2=4, y2=7.
Plug the given values into the formula for slope: m=((7)−(3))/((4)−(6))=4/−2
=−2.
PQ || AB
slope of AB = -2
Find equation knowing slope and point
m= -2
Plug value of the slope and point ( 3 , 1 ) in
Y = m x + b
1.00 = -6 + b
b= 1.00 - -6
b= 7
So the equation will be
Y = -2 x + 7
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