SOLUTION: An employment information service claims the mean annual salary for full-time female workers over age 25 and without a high school diploma is more than $18,500. The annual salari

Algebra ->  Probability-and-statistics -> SOLUTION: An employment information service claims the mean annual salary for full-time female workers over age 25 and without a high school diploma is more than $18,500. The annual salari      Log On


   



Question 1177829: An employment information service claims the mean annual salary for full-time female workers over age 25 and without a high school diploma is more than $18,500. The annual salaries (in dollars) for a random sample of 12 full-time female workers without a high school diploma are provided below. At the 0.10 significance level, is there enough evidence to support the claim that the mean salary is more than $18,500?
Annual Salaries data:
19665

17312

19794

20403

21864

20177
18328

22445

21354

20143

19316

20237

Parameter: ___________________________ Statistic: ________________________________
Ho: _______________________________ Significance Level: ___________________
Ha: ______________________________________________

Plan:
Name of procedure: _________________________________
Check conditions:
Random: ___________, n>30:________ or Assume normal: _____

Mean of model: ___________________
Standard error: ________________________
d.f.:__________________________

Labeled picture of the model:
Direction of test:___________________

Test statistic formula:


Calculation of test statistic and mark in model:


Decision in context:





Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Parameter is mean salary for FTE women workers over 25 with no HS diploma
Ho:Salary is > $18,500
Ha: It is <=$18500
alpha=0.10 P{reject Ho|Ho true}
test statistic is a t 0.95, df=11. We assume normality, random sample and s may be used in place of sigma
critical value t>1.363
test stat t=(x bar-mean)/s/sqrt(n)=(20086.50-18500)/1417.74/sqrt(12)
x bar=$20086.50; s=$1417.74 df=12
t=(2586.50)*sqrt(12)/1417.74=
t=3.88 reject Ho and supports the claim that the mean salary is indeed more than $18,500
p-value 0.0013