Question 1177767: A consulting group believes that 70% of the people in a certain county are satisfied with their health coverage. Assuming that this is true, find the probability that in a random sample of
15 people from the county:
(a) Exactly 10 are satisfied with their health coverage, and interpret.
(b) Not more than 10 are satisfied with their health coverage, and interpret.
(c) What is the expected number of people out of 15 that are satisfied with their health
coverage?
Thank you
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Binomial Distribution: p(satisfied with their health coverage) = .7
Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus
n = 15
(a) P(x = 10) = binompdf(15, .7, 10) = .2061
(b) P(x ≤ 10) = binomcdf(15, .7, 10) = .4845
(c) Expected = .7 * 15 = 10.5 or 10 (rounded down to whole number)
Important You are comfortable using Your Calculator.
Wish You the Best in your Studies.
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