SOLUTION: 2.In a factory, three machines, J, K and L, are used to make biscuits. Machine J makes 25% of the biscuits. Machine K makes 45% of the biscuits. The rest of the biscuits are mad

Algebra ->  Probability-and-statistics -> SOLUTION: 2.In a factory, three machines, J, K and L, are used to make biscuits. Machine J makes 25% of the biscuits. Machine K makes 45% of the biscuits. The rest of the biscuits are mad      Log On


   

Question 1177640: 2.In a factory, three machines, J, K and L, are used to make biscuits.
Machine J makes 25% of the biscuits.
Machine K makes 45% of the biscuits.
The rest of the biscuits are made by machine L.
It is known that 2% of the biscuits made by machine J are broken, 3% of the biscuits made by machine K are broken and 5% of the biscuits made by machine L are broken.
A biscuit is selected at random.
Given that the biscuit is broken, find the probability that it was not made by machine K.
Answer by ikleyn(52782) About Me  (Show Source):
You can put this solution on YOUR website!
.

    P = %280.03%2A0.45%29%2F%280.02%2A0.25+%2B+0.03%2A0.45+%2B+0.05%2A0.3%29 = 0.4030.    ANSWER

The formula I used is self-explanatory.

If you need more explanations, look into this formula and listen attentively what it will tell you . . .

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Solved.