SOLUTION: The length of a rectangle is 4cm more than its width. Its diagonal is 8cm more than its width. What is the width of the rectangle? Show the solution.

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Question 1177621: The length of a rectangle is 4cm more than its width. Its diagonal is 8cm more than its width. What is the width of the rectangle? Show the solution.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
.
(x+8)^2 = x^2 +(x+4)^2 ( Pythagoras theorem)
x^2 +16x +64 = x^2 +x^2 +8x +16
Simplify
x^2-8x -48 =0
(x-12)(x+4)=0
x= 12 or -4
Neglect negative
width =12 cm