Question 1177505: Diana bought 4 pounds of coffee, 5 pounds of sugar, and 10 pounds of flour and received $2.25 change from $30. Nine pounds of flour is $0.50 more than 5 pounds of sugar. Ten pounds of flour and 4 pounds of sugar cost $2 more than 3 pounds of coffee. Find the price for each pound of coffee, sugar, and flour.
I tried the following equations.
4c+5s+10f=27.75
9f=0.50+5s
10f+4s=2+3c
solutions:
c=3.31
s=2.576
f=0.163
Answer by MathLover1(20850)   (Show Source):
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let the price of coffee be  , sugar  , and flour 
if Diana bought  pounds of coffee,  pounds of sugar, and  pounds of flour and received $ change from $ , we have
 ............1)
find the price for each pound of coffee, sugar, and flour:
given:  pounds of flour is $ more than  pounds of sugar
 ..........a)
pounds of flour and  pounds of sugar cost $ more than  pounds of coffee
 ..........b)
from a) and b) we have
 ..........c)
go to a), substitute
 ..........a)
go to
............1), substitute and
go to equation
 ..........c), substitute
do same here
 ..........a)
the price for each pound of coffee is $ , sugar is $ , and flour is $
check:
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