SOLUTION: Given the function {{{y= sqrt(2x+6-1) -1/2 }}}
A) Find out the 5 transformations this graph went through
B) Find the domain and range
C) Using mapping notation, determine the
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-> SOLUTION: Given the function {{{y= sqrt(2x+6-1) -1/2 }}}
A) Find out the 5 transformations this graph went through
B) Find the domain and range
C) Using mapping notation, determine the
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Question 1177494: Given the function
A) Find out the 5 transformations this graph went through
B) Find the domain and range
C) Using mapping notation, determine the 3 key points on f(x) Answer by greenestamps(13203) (Show Source):
A) The question makes no sense; it is not valid to treat this as transformations of a parent graph.
There are 5 steps in evaluating the function for a given value of x:
1) times 2
2) add 6
3) subtract 1
4) take the square root
5) subtract 1/2
But those operations can't be represented as transformations of a graph.
B) The domain is restricted by requiring that the radicand (2x+6-1) be non-negative. You can figure that out.
The range is limited by the fact that a square root is always 0 or positive; that means the minimum value of this function is -1/2. There is clearly no limit to how large the function value can be, so the range is (-1/2,infinity).
C) This is not standard mathematical terminology; it is likely something particular to the textbook or other reference you are using. The one obvious key point on this graph is at the lowest point in the domain; I have no idea what your reference might consider other key points.
